document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349928>Question 349928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At the park, I saw boys and dogs. I saw thirty two heads and 104 legs. How many were dogs and how many boys? Which equations did you use? I got 12 boys and 20 dogs by trial and error but I know that there must be some equations to solve. Please help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250087 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total 104 legs<BR>\n" );
document.write( "32 heads<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let there be x boys & y dogs<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2x+4y=104..................1<BR>\n" );
document.write( "x+y=32......................2<BR>\n" );
document.write( "multiply equation 2 by -2 and add it to equation 1<BR>\n" );
document.write( "-2x-2y=-64<BR>\n" );
document.write( "add<BR>\n" );
document.write( "4y-2y=104-64<BR>\n" );
document.write( "2y=40<BR>\n" );
document.write( "y=20  dogs<BR>\n" );
document.write( "32-20= 12 boys<BR>\n" );
document.write( "...<BR>\n" );
document.write( "12*2+20*4=104<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );