document.write( "Question 349795: the perimeter of a rectangle is 76m. the length is 4m. less than 5 times the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #250049 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=5W-4 \n" ); document.write( "2L+2W=76 \n" ); document.write( "2(5W-4)+2W=76 \n" ); document.write( "10W-8+2W=76 \n" ); document.write( "12W=76+8 \n" ); document.write( "12W=84 \n" ); document.write( "W=84/12 \n" ); document.write( "W=7 ANS. FOR THE WIDTH. \n" ); document.write( "L=5*7-4=35-4=31 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*31+2*7=76 \n" ); document.write( "62+14=76 \n" ); document.write( "76=76 \n" ); document.write( " |