document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349720>Question 349720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 yd longer than its width. If the perimeter of the rectangle is  40 yds, find its area.   I am desperate for help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250019 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HI,<BR>\n" );
document.write( "*Note: the P of a rectangle is the sum of all 4 sides or is generaly written as:<BR>\n" );
document.write( "2*l + 2*w = P and area is wrtten as l*w.<BR>\n" );
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document.write( "The question states the following to be true:<BR>\n" );
document.write( "Let w represent the width<BR>\n" );
document.write( "l = (w + 4)<BR>\n" );
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document.write( "2*(w + 4) + 2*w = 40yds<BR>\n" );
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document.write( "Simplify and solve for w<BR>\n" );
document.write( "4w + 8 = 40yds<BR>\n" );
document.write( "4w = 32yds<BR>\n" );
document.write( "w= 8 yds<BR>\n" );
document.write( "l = 12yds<BR>\n" );
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document.write( "A = l*w<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+8yds+%2A+12+yds+=+96yd%5E2+ ALIGN=MIDDLE  ALT=\"A+=+8yds+%2A+12+yds+=+96yd%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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