document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349757>Question 349757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boater travels 16 miles per hour on the water on a still day.  During one particular windy day, he finds that he travels 48 miles with the wind behind him in the same amount of time that he travels 16 miles into the wind. find the rate of wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250000 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "48=(16+W)T<BR>\n" );
document.write( "T=48/(16+W)<BR>\n" );
document.write( "16=(16-W)T<BR>\n" );
document.write( "T=16/(16-W)<BR>\n" );
document.write( "48/(16+W)=16/(16-W) CROSS MULTIPLY.<BR>\n" );
document.write( "16(16+W)=48(16-W)<BR>\n" );
document.write( "256+16W=768-48W<BR>\n" );
document.write( "16W+48W=768-256<BR>\n" );
document.write( "64W=512<BR>\n" );
document.write( "W=512/64<BR>\n" );
document.write( "W=8 MPH. IS THE RATE OF THE WIND.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "48/(16+8)=16/(16-8)<BR>\n" );
document.write( "48/24=16/8<BR>\n" );
document.write( "2=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );