document.write( "Question 349457: A passenger trains speed is 60me/h and a freight train's speed is 40mi/h. The passenger train traels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip? \n" ); document.write( "
Algebra.Com's Answer #249970 by ankor@dixie-net.com(22740)\"\" \"About 
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A passenger trains speed is 60me/h and a freight train's speed is 40mi/h.
\n" ); document.write( " The passenger train travels the same distance in 1.5 h less time than the freight train.
\n" ); document.write( " How long does each train take to make the trip?
\n" ); document.write( ":
\n" ); document.write( "Let t = time for the freight
\n" ); document.write( "then
\n" ); document.write( "(t-1.5) = time for the pass train to go the same distance
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Pass dist = freight dist
\n" ); document.write( "60(t-1.5) = 40t
\n" ); document.write( "60t - 90 = 40t
\n" ); document.write( "60t - 40t = 90
\n" ); document.write( "20t = 90
\n" ); document.write( "t = \"90%2F20\"
\n" ); document.write( "t = 4.5 hrs for the freight
\n" ); document.write( "then
\n" ); document.write( "4.5 - 1.5 = 3 hrs for the pass
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm solution by finding the distances
\n" ); document.write( "3 * 60 = 180 mi
\n" ); document.write( "4.5*40 = 180 mi \n" ); document.write( "
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