document.write( "Question 39428: 2y/x^2+2x+1 + x/x^2-1 \n" ); document.write( "
Algebra.Com's Answer #24993 by fractalier(6550)\"\" \"About 
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We factor denominators first and get
\n" ); document.write( "2y/x^2+2x+1 + x/x^2-1 =
\n" ); document.write( "2y / (x+1)^2 + x / (x+1)(x-1)
\n" ); document.write( "The lowest common denominator is then
\n" ); document.write( "(x-1)(x+1)^2
\n" ); document.write( "We convert both fractions to that denominator and combine and get
\n" ); document.write( "2y / (x+1)^2 + x / (x+1)(x-1) =
\n" ); document.write( "2y(x-1) / (x-1)(x+1)^2 + x(x+1) / (x-1)(x+1)^2 =
\n" ); document.write( "[2y(x-1) + x(x+1)] / (x-1)(x+1)^2 =
\n" ); document.write( "No further significant simplification can be done...
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