document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349682>Question 349682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i had 114 ft of fencing and wanted the length 2x longer than the width how to i calculate this </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249926 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "If I am understanding the question properly, the 114ft of fencing is to go around a rectangular plot having a width x and length 2x.<BR>\n" );
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document.write( "In general 2*l + 2* w is the Perimeter of a rectangle<BR>\n" );
document.write( "2(2x) + 2x = 114ft<BR>\n" );
document.write( "6x = 114ft<BR>\n" );
document.write( "x = 19ft<BR>\n" );
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document.write( "The 114ft of fencing would work with a rectangular plot 38ft long and 19ft wide<BR>\n" );
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document.write( "Check your answer:<BR>\n" );
document.write( "2*38 + 2*19 + = 114ft </SPAN>\n" );
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