document.write( "Question 349610: A car traveled 120 miles at a certain avarage rate. By increasing its avarage rate by 10mph, it traveled 160 miles in the same time it traveled the 120-mile trip. Find its average rate on the first trip. Show your work.\r
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Algebra.Com's Answer #249901 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Rate*Time=Distance
\n" ); document.write( "\"R%2At=D\"
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\n" ); document.write( "First part of the trip:
\n" ); document.write( "1.\"R%5B1%5D%2At%5B1%5D=120\"
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\n" ); document.write( "Second part of the trip:
\n" ); document.write( "2.\"%28R%5B1%5D%2B10%29%2At%5B1%5D=160\"
\n" ); document.write( "Solve for \"t%5B1%5D\"
\n" ); document.write( "\"R%5B1%5D%2At%5B1%5D%2B10%2At%5B1%5D=160\"
\n" ); document.write( "\"120%2B10%2At%5B1%5D=160\"
\n" ); document.write( "\"10%2At%5B1%5D=40\"
\n" ); document.write( "\"highlight%28t%5B1%5D=4%29\"
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\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"R%5B1%5D%2A4=120\"
\n" ); document.write( "\"R%5B1%5D=30\"mph
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