document.write( "Question 349602: Please help me. \r
\n" ); document.write( "\n" ); document.write( "sqrt ( x - 2 ) + 3 = sqrt ( 4x + 1 ) \r
\n" ); document.write( "\n" ); document.write( "I know we're supposed to get one radical by itself, but one already is. And then the power rule to eliminate the radicals. But from there, I'm stuck. \r
\n" ); document.write( "\n" ); document.write( "Thank you for your time.
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Algebra.Com's Answer #249883 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt+%28+x+-+2+%29+%2B+3+=+sqrt+%28+4x+%2B+1+%29\"
\n" ); document.write( "Square both sides.
\n" ); document.write( " \"%28x-2%29%2B6sqrt%28x-2%29%2B9=4x%2B1\"
\n" ); document.write( "\"6sqrt%28x-2%29=3x-6\"
\n" ); document.write( "Square both sides again,
\n" ); document.write( "\"36%28x-2%29=9x%5E2-36x%2B36\"
\n" ); document.write( "\"36x-72=9x%5E2-36x%2B36\"
\n" ); document.write( "\"9x%5E2-72x%2B108=0\"
\n" ); document.write( "\"x%5E2-8x%2B12=0\"
\n" ); document.write( "\"%28x-2%29%28x-6%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x-2=0\"
\n" ); document.write( "\"highlight%28x=2%29\"
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\n" ); document.write( "\"x-6=0\"
\n" ); document.write( "\"highlight%28x=6%29\"
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