document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349562>Question 349562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 800 less than three times the other, and their sum is 1200. Find the numbers.\r<BR>\n" );
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document.write( "Please show me the solutions. As simplify as it can be... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249842 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one number be x<BR>\n" );
document.write( "the other number will be 1200-x. ( Because the sum of both is 1200)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "one number is 800 less than the 3 times the other.<BR>\n" );
document.write( "The other number is 1200-x<BR>\n" );
document.write( "3 times other = 3(1200-x)<BR>\n" );
document.write( "less 800<BR>\n" );
document.write( "= 3(1200-x) -800<BR>\n" );
document.write( "x=3(1200-x)-800<BR>\n" );
document.write( "x=3600-3x-800<BR>\n" );
document.write( "x+3x= 2400<BR>\n" );
document.write( "4x = 2400<BR>\n" );
document.write( "divide by 4<BR>\n" );
document.write( "x= 2400/4<BR>\n" );
document.write( "x=600<BR>\n" );
document.write( "if one number is 600, then other is 1200-x=600. </SPAN>\n" );
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