document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349563>Question 349563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pq and rs are two parallel horizontal chords 6 cm and 8 cm long in the upper half of a circle.if the radius of the circle is 5cm . the distance in cm between the chords is \r<BR>\n" );
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document.write( "A  1    B   2     C   3    D   4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249840 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius bisects the chord. The chords are of length 8 & 6.<BR>\n" );
document.write( "The radius,perpendicular distance from center to chord and the chord form a right triangle.<BR>\n" );
document.write( "Apply pythagorean formula<BR>\n" );
document.write( "for both triangles\r<BR>\n" );
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document.write( "Radius  is the hypotenuse.<BR>\n" );
document.write( "5^2-4^2<BR>\n" );
document.write( "25-16=9<BR>\n" );
document.write( "sqrt9 = 3<BR>\n" );
document.write( "....<BR>\n" );
document.write( "5^2-3^2<BR>\n" );
document.write( "25-9=16<BR>\n" );
document.write( "sqrt16=4<BR>\n" );
document.write( "the distance between the chords = 1 in. </SPAN>\n" );
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