document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349541>Question 349541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a person is walking 6 miles per hour and another is riding a bike 12 MPH how far apart will they be after 10 minutes.  Assuming they start next to each other and head in opposite directions.<BR>\n" );
document.write( "Having trouble writing the equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249824 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> walk speed = 6mph<BR>\n" );
document.write( "cycling = 12mph<BR>\n" );
document.write( "they are going in opposite directions<BR>\n" );
document.write( "so effective speed = 12+6 = 18 mph.<BR>\n" );
document.write( "time = 10 minutes<BR>\n" );
document.write( "= 10/60 = 1/6 hour<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Distance = speed * time<BR>\n" );
document.write( "Distance = 18*1/6<BR>\n" );
document.write( "= 3 miles apart </SPAN>\n" );
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