document.write( "Question 39536: solve the pairs of equations using the addition or subtraction method. \r
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document.write( "3w - 2z = 38\r
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document.write( "z = 2w - 18\r
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document.write( "This is as far as I got, but I don't know if it's right. \r
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document.write( "3w - 2z = 38
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document.write( "2w + z = 18 \n" );
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Algebra.Com's Answer #24982 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! (1) 3w - 2z = 38 \n" ); document.write( "(2) z = 2w -18 \n" ); document.write( "subtract 2w from both sides of (2) \n" ); document.write( "z -2w = -18 \n" ); document.write( "rearrange the left side \n" ); document.write( "-2w + z = -18 \n" ); document.write( "now we have \n" ); document.write( "(1) 3w - 2z = 38 \n" ); document.write( "(2) -2w + z = -18 \n" ); document.write( "multiply both sides of (2) by 2 \n" ); document.write( "(1) 3w - 2z = 38 \n" ); document.write( "(2) -4w + 2z = -36 \n" ); document.write( "add (1) to (2) \n" ); document.write( " -w = 2 \n" ); document.write( "multiply both sides by -1 \n" ); document.write( " w = -2 \n" ); document.write( "substitute w = -2 in (2) \n" ); document.write( "z = 2*(-2) -18 \n" ); document.write( "z = -4 -18 \n" ); document.write( "z = -22 \n" ); document.write( "check by substituting w and z in (1) \n" ); document.write( "3*(-2) - 2*(-22) = 38 \n" ); document.write( "-6 + 44 = 38 \n" ); document.write( "38 = 38 \n" ); document.write( "OK \n" ); document.write( " |