document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349366>Question 349366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> fifteen days after alan begin a diet he weighed 176 lb. after 45 days he weighed 170lb. a how much did he weigh at the beginning of the diet b. at this rate when will he weigh 165lb<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249775 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) 176 - 170 = 6 lbs; 45 - 15 = 30 days\r<BR>\n" );
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document.write( "Solve by ratio:\r<BR>\n" );
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document.write( "6/30 = x/15 .....solve for x\r<BR>\n" );
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document.write( "x = 3 lbs .....so, in 15 days time, he is able to lose 3 lbs\r<BR>\n" );
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document.write( "176 lbs + 3 lbs = 179 lbs ......weight a day 0; beginning of diet\r<BR>\n" );
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document.write( "B) 179 - 165 = 14 lbs\r<BR>\n" );
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document.write( "Solve by ratio:\r<BR>\n" );
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document.write( "3 lbs /15 days = 14 lbs / x ......solve for x\r<BR>\n" );
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document.write( "x = 14 (15) / 3\r<BR>\n" );
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document.write( "x = 70 days<BR>\n" );
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