document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349443>Question 349443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Imogene's car traveled 280 mi averaging a certain speed. If the car had gone 5 mph faster, the trip would have taken 1 hour less. Find the average speed.\r<BR>\n" );
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document.write( "i let r= rate of average speed<BR>\n" );
document.write( "i let r+5= rate could have been 1 hour less\r<BR>\n" );
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document.write( "280/r + 280/(r+5)= 280/r + 280/(r+5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249766 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Imogene's car traveled 280 mi averaging a certain speed. If the car had gone 5 mph faster, the trip would have taken 1 hour less. Find the average speed.\r<BR>\n" );
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document.write( "let rate be x<BR>\n" );
document.write( "if rate is increase by 5 the new rate = x+5 mph<BR>\n" );
document.write( "Distance = 280 miles<BR>\n" );
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document.write( "Time taken by old rate - time taken by new rate =1<BR>\n" );
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document.write( "280/x-280/(x+5)=1<BR>\n" );
document.write( "280(x+5)-280x /x(x+5) =1<BR>\n" );
document.write( "280x+1400-280x=x(x+5)\r<BR>\n" );
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document.write( "1400 = x^2+5x<BR>\n" );
document.write( "x^2+5x-1400=0<BR>\n" );
document.write( "x^2++40x-35x-1400=0<BR>\n" );
document.write( "x(x+40)-35(x+40)=0<BR>\n" );
document.write( "(x+40)(x-35)=0<BR>\n" );
document.write( "So x = 35 mph the original rate </SPAN>\n" );
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