document.write( "Question 349423: An angle exceeds one-half its complement by 12 degrees. Find the angle \n" ); document.write( "
Algebra.Com's Answer #249762 by Earlsdon(6294)\"\" \"About 
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Let the angle be A, then...
\n" ); document.write( "\"A+=+%28%2890-A%29%2F2%29%2B12\" \"An angle (A) exceeds one half its complement (\"%2890-A%29%2F2\") by 12 degrees (\"%28%2B12%29\")\".
\n" ); document.write( "\"A+=+%28%2890-A%29%2F2%29%2B12\" Multiply through by 2.
\n" ); document.write( "\"2A+=+90-A%2B24\" Add A to both sides.
\n" ); document.write( "\"3A+=+90%2B24\" Simplify.
\n" ); document.write( "\"3A+=+114\" Divide both sides by 3.
\n" ); document.write( "\"A+=+38\"
\n" ); document.write( "The angles is 38 degrees.
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