document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349430>Question 349430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of a rectangle is 3 yards more than twice its width, and the perimeter of the rectangle is 36 yards, find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249759 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x<BR>\n" );
document.write( "length = 2x+3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "2*(x+2x+3)=36<BR>\n" );
document.write( "2(3x+3)=36<BR>\n" );
document.write( "6x+6=36<BR>\n" );
document.write( "6x=30<BR>\n" );
document.write( "x= 5 yards the width<BR>\n" );
document.write( "2x+3 = 10+3 = 13 yards the length </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );