document.write( "Question 349249: Suppose that the width of a certain rectangle is three-fourths of its length, and the area of that same rectangle is 48 square meters. What is the length and the width of this rectangle? \n" ); document.write( "
Algebra.Com's Answer #249694 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Length = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Width = (3/4)x = (3x/4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area = 48m^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use A = L*W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "48 = x(3x/4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After solving for, we get x = -8 and x = 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Disregard x = -8 since length and width are distances and distance is positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The length is 8 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The width is (3*8)/4 or 6 meters.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |