document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349189>Question 349189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A landscaping company is laying out a triangular flower bed. The height of the triangle is 12ft. What lengths of the base will make the area at least <BR>\n" );
document.write( "168ft-sq.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249648 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A landscaping company is laying out a triangular flower bed. The height of the triangle is 12ft. What lengths of the base will make the area at least <BR>\n" );
document.write( "168ft-sq. <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since area of any triangle is (1/2)bh<BR>\n" );
document.write( "where<BR>\n" );
document.write( "b is the length of the base<BR>\n" );
document.write( "h is the height<BR>\n" );
document.write( ".<BR>\n" );
document.write( "From the above, our equation is:<BR>\n" );
document.write( "168 = (1/2)b(12)<BR>\n" );
document.write( "168 = b(6)<BR>\n" );
document.write( "168/6 = b<BR>\n" );
document.write( "28 feet = b<BR>\n" );
document.write( ".<BR>\n" );
document.write( "So, base has to be 28 feet or greater<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );