document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348264>Question 348264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rationalize the numerator. Then, simplify the result. 2&#8730;3+&#8730;3/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249630 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No need to rationalize anything here.\r<BR>\n" );
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document.write( "2&#8730;3+&#8730;3/3 =\r<BR>\n" );
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document.write( "Use the same rules for addition of fractions that your learned a long time ago.\r<BR>\n" );
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document.write( "LCD = 3\r<BR>\n" );
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document.write( "Applying the addition rules for fractions, we get (6&#8730;3 + &#8730;3)/7 = 7&#8730;3/3. </SPAN>\n" );
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