document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39529>Question 39529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the tempature outside is dropping at a constant rate.At noon, the tempature is 70 F,and it drops to 58F at 5pm ..How much did the tempature change each hour? \r<BR>\n" );
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document.write( "I thought it was half hour ,but i was wrong.Sorry the 5 did not come up in my other post.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24963 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, we can logic it out...<BR>\n" );
document.write( "If the temperature drops from 70 to 58, it dropped 12 degrees.<BR>\n" );
document.write( "If it took 5 hours, then we divide 12 degress by 5 hours, and get<BR>\n" );
document.write( "12 / 5 = 2.4 degrees per hour<BR>\n" );
document.write( "We can look at it another way too...<BR>\n" );
document.write( "(70 - 58) / (5 - 0) = 2.4 </SPAN>\n" );
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