document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348648>Question 348648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer's silo is the shape of a cylinder with a hemisphere as the roof. If the height of the silo is 78 feet and the radius of the hemisphere is r feet, express the volume of the silo as a function of r. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249600 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The silo is composed of a cylinder and a hemisphere.\r<BR>\n" );
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document.write( "The total volume of the silo = vol. of cylinder + vol. of hemisphere\r<BR>\n" );
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document.write( "The volume of a cylinder is given by pi*r^(2)*H where r is the radius of the cylinder and H is the height of the cylinder.\r<BR>\n" );
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document.write( "For the silo's cylinder r = r and H = 78 - r. Hence its volume = pi r^(2)*(78 - r)\r<BR>\n" );
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document.write( "The volume of a sphere of radius r is (4/3)pi*r^(3). Hence the volume of a hemisphere is (2/3)pi*r^(3).\r<BR>\n" );
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document.write( "Hence the volume of the silo = pi r^(2) (78 - r) + (2/3)pi*r^(3)\r<BR>\n" );
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document.write( "= pi*r^(2) [ 78 - r/3]<BR>\n" );
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