document.write( "Question 349148: How do you work the problem... Y=x+8 and X+Y=2 \n" ); document.write( "
Algebra.Com's Answer #249585 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1.\"y=x%2B8+\"
\n" ); document.write( "2.\"+x%2By=2\"
\n" ); document.write( "Use substitution, substitute eq. 1 into eq. 2 and solve for \"x\".
\n" ); document.write( "\"x%2B%28x%2B8%29=2\"
\n" ); document.write( "\"2x%2B8=2\"
\n" ); document.write( "\"2x=-6\"
\n" ); document.write( "\"highlight%28x=-3%29\"
\n" ); document.write( "Now use eq. 1 to solve for y.
\n" ); document.write( "\"y=-3%2B8\"
\n" ); document.write( "\"highlight%28y=5%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Verify by plugging the solutions into the original equations.
\n" ); document.write( "\"y=x%2B8\"
\n" ); document.write( "\"5=-3%2B8\"
\n" ); document.write( "\"5=5\"
\n" ); document.write( "True.
\n" ); document.write( "\"x%2By=2\"
\n" ); document.write( "\"-3%2B5=2\"
\n" ); document.write( "\"2=2\"
\n" ); document.write( "True.
\n" ); document.write( "It's a good solution.
\n" ); document.write( "
\n" );