document.write( "Question 349130: A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed with 2 pounds of cherry candy to obtain a mixture that is priced at $10 per pound? \n" ); document.write( "
Algebra.Com's Answer #249571 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed with 2 pounds of cherry candy to obtain a mixture that is priced at $10 per pound?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "amount A * price A + amount B * price B = amount C * price C \n" ); document.write( "let A = peppermint candy, B = cherry candy, C = mixture of both \n" ); document.write( "A + 2 = weight in pounds (lbs) of the mixture of candy \n" ); document.write( "A * $8/lb + 2 lbs * $14/lb = (A + 2) lbs * $10/lb \n" ); document.write( "8A + 28 = (A + 2) * 10 \n" ); document.write( "8A + 28 = 10A + 20 \n" ); document.write( "8A - 10A = 20 - 28 \n" ); document.write( "-2A = -8 \n" ); document.write( "2A = 8 \n" ); document.write( "A = 4 lbs peppermint candy\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |