document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349098>Question 349098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph 2y-5x<13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249524 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you need to solve for y.\r<BR>\n" );
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document.write( "then you can graph it.\r<BR>\n" );
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document.write( "2y-5x < 13\r<BR>\n" );
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document.write( "add 5x to both sides to get:\r<BR>\n" );
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document.write( "2y < 5x + 13\r<BR>\n" );
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document.write( "divide both sides by y to get:\r<BR>\n" );
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document.write( "y < (5x+13)/2\r<BR>\n" );
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document.write( "now you can graph the equation of:\r<BR>\n" );
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document.write( "y = (5x+13)/2.\r<BR>\n" );
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document.write( "any value of y below the the graph of that equation is good.\r<BR>\n" );
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document.write( "any value of y on or higher than the graph of that equation is not good.\r<BR>\n" );
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document.write( "you would shade the area of the graph below the line to indicate that is the good region.\r<BR>\n" );
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document.write( "your graph would look like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C%285x%2B13%29%2F2%29 ALIGN=MIDDLE  ALT=\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C%285x%2B13%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "to prove your graph is good, take the value of x = 0 and substitute it in your equation to get:\r<BR>\n" );
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document.write( "y = (5x+13)/2 which becomes y = 13/2 which becomes y = 6.5 which is confirmed by the graph of the equation crossing the y-axis at x = 6.5.\r<BR>\n" );
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document.write( "to further prove your graph is good, take the value of y = 0 and substitute it in your equation to get:\r<BR>\n" );
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document.write( "0 = (5x+13)/2.\r<BR>\n" );
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document.write( "multiply both sides of the equation to get:\r<BR>\n" );
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document.write( "0 = 5x + 13\r<BR>\n" );
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document.write( "subtract 13 from both sides of the equation to get:\r<BR>\n" );
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document.write( "-13 = 5x\r<BR>\n" );
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document.write( "divide both sides of the equation by 5 to get:\r<BR>\n" );
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document.write( "-13/5 = x\r<BR>\n" );
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document.write( "-13/5 is equal to -2.6 which is the value of y when x = 0 and is confimred by the graph crossing the x-axis at approximately that point.\r<BR>\n" );
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document.write( "you don't graph the inequality directly.\r<BR>\n" );
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document.write( "you graph the equality and then apply logic so see where the values of y can lie.\r<BR>\n" );
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document.write( "in this case the values of y that lie below the equation are the values that are valid.\r<BR>\n" );
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document.write( "take any value of x.\r<BR>\n" );
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document.write( "find the value of y that lies on the graph of the equation of y = (5x+13)/2.\r<BR>\n" );
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document.write( "for that value of x, any value of y less than that will be below the line, and any value of y greater than that will be above the line.\r<BR>\n" );
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document.write( "the region that is valid for the equation y < (5x+13)/2 will be below the line.\r<BR>\n" );
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