document.write( "Question 39513: How do you compute the intercepts of a quadratic function?\r
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Algebra.Com's Answer #24952 by josmiceli(19441) $\"\"$ $\"About$

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y(x) = Ax^2 + Bx + C
\n" ); document.write( "y(0) will be the y-intercept. There should be just one.
\n" ); document.write( "This is found by setting x = 0 in the equation, so
\n" ); document.write( "y(0) = A(0) + B(0) + C
\n" ); document.write( "y(0) = C
\n" ); document.write( "The x-intercept(s) is found by setting y(x) = 0
\n" ); document.write( "There may be 0, 1, or 2 x-intercepts
\n" ); document.write( "Ax^2 + Bx + C = 0 solve for x
\n" ); document.write( "The formula is
\n" ); document.write( " $\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4%2AA%2AC+%29%29%2F%282%2AA%29+\"$ \n" ); document.write( "

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