document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349087>Question 349087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve the below problem but I have question.\r<BR>\n" );
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document.write( "-7(5y – 2) > 6(6y-1)\r<BR>\n" );
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document.write( "I first multiplied\r<BR>\n" );
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document.write( "-35y- -14> 36y-6\r<BR>\n" );
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document.write( "Then added 6 to both sides\r<BR>\n" );
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document.write( "-35y- -14+6>36y -6+6\r<BR>\n" );
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document.write( "-35y- -8>36y\r<BR>\n" );
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document.write( "I am confused, I am not sure if the next step is correct.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249513 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I will solve it for you and then you can see where you went wrong.\r<BR>\n" );
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document.write( "problem is:\r<BR>\n" );
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document.write( "-7(5y – 2) > 6(6y-1) which can also be written as:\r<BR>\n" );
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document.write( "-7*(5*y – 2) > 6*(6*y-1).\r<BR>\n" );
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document.write( "The * indicates multiplication and can make things clearer if there is any ambiguity in how the formula is shown.\r<BR>\n" );
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document.write( "remove parentheses to get:\r<BR>\n" );
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document.write( "-35*y + 14 > 36*y - 6\r<BR>\n" );
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document.write( "add 6 to both sides of the equation to get:\r<BR>\n" );
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document.write( "-35*y + 20 > 36*y\r<BR>\n" );
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document.write( "add 35*y to both sides of the equation to get:\r<BR>\n" );
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document.write( "20 > 36*h + 35*y \r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "20 > 71*y\r<BR>\n" );
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document.write( "divide both sides of the equation by 71 to get:\r<BR>\n" );
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document.write( "20/71 > y\r<BR>\n" );
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document.write( "if 20/71 > y, then:\r<BR>\n" );
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document.write( "y < 20/71\r<BR>\n" );
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document.write( "that should be your answer.\r<BR>\n" );
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document.write( "you confirm by substituting in the original equation to see if the equation is true.\r<BR>\n" );
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document.write( "take 3 values for y.\r<BR>\n" );
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document.write( "pick values that are easy to calculate wherever possible.\r<BR>\n" );
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document.write( "take y = 0 which is smaller than 20/71\r<BR>\n" );
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document.write( "take y = 20/71 which is equal to 20/71\r<BR>\n" );
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document.write( "take y = 1 which is greater than 20/71\r<BR>\n" );
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document.write( "if y is smaller than 20/71, the original equation should be true.\r<BR>\n" );
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document.write( "if y is greater than or equal to 20/71, the original equation should be false.\r<BR>\n" );
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document.write( "the original equation is:\r<BR>\n" );
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document.write( "-7(5y – 2) > 6(6y-1)\r<BR>\n" );
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document.write( "substitute 0 for y to get:\r<BR>\n" );
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document.write( "14 > -6 which is true.\r<BR>\n" );
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document.write( "substitute 1 for y to get:\r<BR>\n" );
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document.write( "-21 > 30 which is false.\r<BR>\n" );
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document.write( "substitute 20/71 for y to get:\r<BR>\n" );
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document.write( "4.14084507 > 4.14084507 which is false.\r<BR>\n" );
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document.write( "confirmation of y < 20/71 is good since:\r<BR>\n" );
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document.write( "when y < 20/71, the original equation is true.\r<BR>\n" );
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document.write( "when y >= 20/71, the original equation is false.\r<BR>\n" );
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