document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349090>Question 349090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gideon is 30 yrs. younger than father. His mother is 3 times as old as his son. Find Gideons age if his father is 2 yrs. older than his mother. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249512 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let father be x years<BR>\n" );
document.write( "Gideon = x-30<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Mother = 3(x-30)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x=3(x-30)+2<BR>\n" );
document.write( "x=3x-90+2<BR>\n" );
document.write( "3x-x=90-2<BR>\n" );
document.write( "2x=88<BR>\n" );
document.write( "x= 44 fathers age<BR>\n" );
document.write( "Gideon = 44-30<BR>\n" );
document.write( "=14 years\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );