document.write( "Question 349062: Find a two digit number such that the tens digit exceeds the unit digit by 3 and the number is 4 less than the sum of the squares of its digits. \n" ); document.write( "
Algebra.Com's Answer #249503 by mananth(16946)\"\" \"About 
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let units digit be y
\n" ); document.write( "ten's digit be x
\n" ); document.write( "...
\n" ); document.write( "x=y+3
\n" ); document.write( "x-y=3
\n" ); document.write( "...
\n" ); document.write( "10x+y= x^2+y^2-4
\n" ); document.write( "x^2+y^2-y-10x-4 =0
\n" ); document.write( "plug value of x
\n" ); document.write( "(y+3)^2+y^2-y-10(y+3)-4=0
\n" ); document.write( "y^2+6y+9+y^2-y-10y-30-4=0
\n" ); document.write( "2y^2-5y-25=0
\n" ); document.write( "2y^2-10y+5y-25=0
\n" ); document.write( "2y(y-5)+5(y-5)=0
\n" ); document.write( "(2y+5)(y-5)=0
\n" ); document.write( "y=5
\n" ); document.write( "x=8
\n" ); document.write( "the number is 85
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