document.write( "Question 349040: Solve this equation: x/x+1 + 2/x=1 \n" ); document.write( "
Algebra.Com's Answer #249481 by haileytucki(390)\"\" \"About 
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(x)/(x+1)+(2)/(x)=1\r
\n" ); document.write( "\n" ); document.write( "Find the LCD (least common denominator) of (x)/((x+1))+(2)/(x)+1.
\n" ); document.write( "Least common denominator: x(x+1)\r
\n" ); document.write( "\n" ); document.write( "Multiply each term in the equation by x(x+1) in order to remove all the denominators from the equation.
\n" ); document.write( "(x)/(x+1)*x(x+1)+(2)/(x)*x(x+1)=1*x(x+1)\r
\n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors.
\n" ); document.write( "x^(2)+2x+2=1*x(x+1)\r
\n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by multiplying out all the terms.
\n" ); document.write( "x^(2)+2x+2=x^(2)+x\r
\n" ); document.write( "\n" ); document.write( "Move all terms not containing x to the right-hand side of the equation.
\n" ); document.write( "x^(2)+2x+2-x^(2)-x=0\r
\n" ); document.write( "\n" ); document.write( "Since x^(2) and -x^(2) are like terms, add -x^(2) to x^(2) to get 0.
\n" ); document.write( "0+2x+2-x=0\r
\n" ); document.write( "\n" ); document.write( "Since 2x and -x are like terms, add -x to 2x to get x.
\n" ); document.write( "x+2=0\r
\n" ); document.write( "\n" ); document.write( "Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides.
\n" ); document.write( "x=-2
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