document.write( "Question 349040: Solve this equation: x/x+1 + 2/x=1 \n" ); document.write( "
Algebra.Com's Answer #249481 by haileytucki(390)![]() ![]() You can put this solution on YOUR website! (x)/(x+1)+(2)/(x)=1\r \n" ); document.write( "\n" ); document.write( "Find the LCD (least common denominator) of (x)/((x+1))+(2)/(x)+1. \n" ); document.write( "Least common denominator: x(x+1)\r \n" ); document.write( "\n" ); document.write( "Multiply each term in the equation by x(x+1) in order to remove all the denominators from the equation. \n" ); document.write( "(x)/(x+1)*x(x+1)+(2)/(x)*x(x+1)=1*x(x+1)\r \n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors. \n" ); document.write( "x^(2)+2x+2=1*x(x+1)\r \n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by multiplying out all the terms. \n" ); document.write( "x^(2)+2x+2=x^(2)+x\r \n" ); document.write( "\n" ); document.write( "Move all terms not containing x to the right-hand side of the equation. \n" ); document.write( "x^(2)+2x+2-x^(2)-x=0\r \n" ); document.write( "\n" ); document.write( "Since x^(2) and -x^(2) are like terms, add -x^(2) to x^(2) to get 0. \n" ); document.write( "0+2x+2-x=0\r \n" ); document.write( "\n" ); document.write( "Since 2x and -x are like terms, add -x to 2x to get x. \n" ); document.write( "x+2=0\r \n" ); document.write( "\n" ); document.write( "Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides. \n" ); document.write( "x=-2 \n" ); document.write( " |