document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349032>Question 349032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation for. Mrs Smith rode the bus 720 miles in 3 days. On the first day she rode 3 times as far as she did on the second day. On the third day, she rode 2 times as far as she did the second day. How far did she travel each day? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249472 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+3x+2x=720\r<BR>\n" );
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document.write( "Since x and 3x are like terms, add 3x to x to get 4x.<BR>\n" );
document.write( "4x+2x=720\r<BR>\n" );
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document.write( "Since 4x and 2x are like terms, add 2x to 4x to get 6x.<BR>\n" );
document.write( "6x=720\r<BR>\n" );
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document.write( "Divide each term in the equation by 6.<BR>\n" );
document.write( "(6x)/(6)=(720)/(6)\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "x=(720)/(6)\r<BR>\n" );
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document.write( "Simplify the right-hand side of the equation by simplifying each term.<BR>\n" );
document.write( "x=120<BR>\n" );
document.write( "First day 120*3=360 miles<BR>\n" );
document.write( "Second Day =    120 miles<BR>\n" );
document.write( "Thrid Day=120*2=240 miles </SPAN>\n" );
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