document.write( "Question 39405: I'm not sure if I answered this problem right:
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document.write( " The square of the first consecutive integer plus the square of the third consecutive integer equals 486 more than the square of the consecutive integer. find the integers.
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document.write( "Here's my work:
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document.write( " x^2 +x^2 +4X + 4 = 486 + x^2 +2x +1
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document.write( " 2x^2 + 4x +4 = 487 + x^2 + 2x
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document.write( " Subtract x^2 + 2x + 487 from each side
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document.write( " x^2 + 2x - 483 = 0
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document.write( " (x+23) (x-21)
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document.write( " x = -23 x=21 \n" );
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Algebra.Com's Answer #24947 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! GOOD TO SEE YOUR ATTEMP.KEEP IT UP!SEE MY COMMENTS BELOW \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "I'm not sure if I answered this problem right: \n" ); document.write( "The square of the first consecutive integer plus the square of the third consecutive integer equals 486 more than the square of the consecutive integer. find the integers. \n" ); document.write( "Here's my work: \n" ); document.write( "x^2 + (x+2)^2 = 486 + (x+1)^2 \n" ); document.write( "x^2 +x^2 +4X + 4 = 486 + x^2 +2x +1 \n" ); document.write( "2x^2 + 4x +4 = 487 + x^2 + 2x \n" ); document.write( "Subtract x^2 + 2x + 487 from each side \n" ); document.write( "x^2 + 2x - 483 = 0 \n" ); document.write( "(x+23) (x-21) \n" ); document.write( "x = -23 x=21..EXCELLENT ! NOTHING BETTER COULD BE DONE.KEEP IT UP \n" ); document.write( "SO THE INTEGERS ARE 21,22,23 ................OR.......-23,-22,-21 \n" ); document.write( " |