document.write( "Question 349019: In the proportion 5/h-k/14, what happens to the value of h as the value of k increases....please explain....Thanks \n" ); document.write( "
Algebra.Com's Answer #249465 by jim_thompson5910(35256)\"\" \"About 
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I assume you mean \"5%2Fh=k%2F14\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Fh=k%2F14\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5%2A14=kh\" Cross multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"70=kh\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"kh=70\" Flip the equation.\r
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\n" ); document.write( "\n" ); document.write( "Now if we increase 'k', then will \"kh=70\" if we leave 'h' alone (ie don't change 'h')? The answer is \"no\". So in order for the equation to remain true, the value of 'h' must decrease while 'k' increases\r
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\n" ); document.write( "\n" ); document.write( "Eg: Let k=10 and h=7. So \"kh=10%2A7=70\". Now if k=14 (k just increased by 4), then \"h=70%2F14=5\" which means that 'h' decreased by 2.\r
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\n" ); document.write( "\n" ); document.write( "So in summary, as 'k' increases, 'h' decreases. \r
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\n" ); document.write( "\n" ); document.write( "Note: This works the other way as well. If 'h' were to increase, then 'k' will decrease to keep the equation true.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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