document.write( "Question 39430: In rectangle ABCD, diagonal line BD is one more than twice lined BC. Line CD is 7 more than line BC. find line AB. \n" ); document.write( "
Algebra.Com's Answer #24946 by venugopalramana(3286) You can put this solution on YOUR website! In rectangle ABCD, diagonal line BD=D SAY is one more than twice lined BC=W SAY. Line CD=L SAY is 7 more than line BC. find line AB. \n" ); document.write( "LET AB=CD=L \n" ); document.write( "BC=DA=W \n" ); document.write( "HENCE BD^2=D^2=L^2+W^2 \n" ); document.write( "WE ARE GIVEN THAT D=2W+1 AND L=W+7...SO \n" ); document.write( "(2W+1)^2=(W+7)^2+W^2 \n" ); document.write( "4W^2+1+4W=W^2+49+14W+W^2=2W^2+14W+49 \n" ); document.write( "2W^2-10W-48=0 \n" ); document.write( "W^2-5W-24=0 \n" ); document.write( "W^2-8W+3W-24=0 \n" ); document.write( "W(W-8)+3(W-8)=0 \n" ); document.write( "(W-8)(W+3)=0 \n" ); document.write( "W=8=BC \n" ); document.write( "AB=L=W+7=15 \n" ); document.write( " |