document.write( "Question 349014: write the equation of the line passing through the point (-3,1) which is perpendicular to line 7y-5x-7=0 \n" ); document.write( "

Algebra.Com's Answer #249457 by mananth(16946) $\"\"$ $\"About$

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(-3,1) which is perpendicular to line 7y-5x-7=0
\n" ); document.write( ".
\n" ); document.write( " 7y-5x-7=0
\n" ); document.write( "7y=5x+7
\n" ); document.write( "/7
\n" ); document.write( "y= 5x/7 +1
\n" ); document.write( "slope = 5/7
\n" ); document.write( "...
\n" ); document.write( "The slope of line perpendicular to this line will be -7/5
\n" ); document.write( "point ( -3,1)
\n" ); document.write( "Plug value of a,y & m to get value of b
\n" ); document.write( "in y= mx+b
\n" ); document.write( "1=-7/5 * -3 +b
\n" ); document.write( "1=21/5 +b
\n" ); document.write( "1-21/5 = b
\n" ); document.write( "-16/5 =b
\n" ); document.write( "The equation will be
\n" ); document.write( "y= -7/5 x -16/5 \r
\n" ); document.write( "\n" ); document.write( " $\"graph%28500%2C500%2C-20%2C20%2C-20%2C20%2C%28%28-7x%2F5%29-%2816%2F5%29%29%29\"$ \n" ); document.write( "

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