document.write( "Question 4988: Can you please explain how to this works out: \"log%282%2CX%29\",\"log%284%2CX%29\" \n" ); document.write( "
Algebra.Com's Answer #2494 by ichudov(507)\"\" \"About 
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Sure, say \"X+=+4%5EY\" that means that \"Y=log%28+4%2C+X+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"X+=+4%5EY+=+%282%2A2%29%5EY+=+2%5EY%2A2%5EY\"
\n" ); document.write( "\"X+=+2%5EY%2A2%5EY\"\r
\n" ); document.write( "\n" ); document.write( "take a log with base 2 of the right part of the formula above\r
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\n" ); document.write( "\n" ); document.write( "Since \"log%28+2%2C+2%5EY+%29\" is Y, we have\r
\n" ); document.write( "\n" ); document.write( "\"log%28+2%2C+X+%29+=+2Y\"\r
\n" ); document.write( "\n" ); document.write( "Y, as we know is \"log%28+4%2C+X+%29\", so \r
\n" ); document.write( "\n" ); document.write( "\"log%28+2%2C+X+%29+=+2%2Alog%28+4%2C+X+%29\"
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