document.write( "Question 348800: 2 shuttles take off, one .5 hours after the other. The later shuttle travels 300 mph faster than the previous. At 5 hours they are at the same altitude. What is the previous shuttle's speed in mph? \n" ); document.write( "
Algebra.Com's Answer #249380 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=R*5 FOR THE FIRST SHUTTLE. \n" ); document.write( "D=(R+300)(5-.5) \n" ); document.write( "5R=(R+300)4.5 \n" ); document.write( "5R=4.5R+1,350 \n" ); document.write( "5R-4.5R=1,350 \n" ); document.write( ".5R=1,350 \n" ); document.write( "R=1.350/.5 \n" ); document.write( "R=2,700 MPH ANS. FOR THE RATE OF THE FIRST SHUTTLE. \n" ); document.write( "2,700+300=3,000 MPH. ANS FOR THE SECOND SHUTTLE. \n" ); document.write( "PROOF: \n" ); document.write( "5*2,700=3,000*4.5 \n" ); document.write( "13,500=13,500 \n" ); document.write( " \n" ); document.write( " |