document.write( "Question 348728: The circumference of a rear wheel of a certain wagon is 3 feet longer than the circumference of the front wheel. The rear wheel makes 100 fewer revolutions than the front wheel in travelling a distance of 6000 feet, Find the circumference of each wheel. \n" ); document.write( "
Algebra.Com's Answer #249349 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"c\" = circumference of the front wheel
\n" ); document.write( "Then \"c+%2B+3\" = circumference of the rear wheel
\n" ); document.write( "When the front wheel travels \"6000\" ft, it makes
\n" ); document.write( "\"6000%2Fc\" revolutions
\n" ); document.write( "The rear wheel makes \"6000%2Fc+-+100\" revolutions
\n" ); document.write( "--------------------------------------
\n" ); document.write( "\"%286000%2Fc+-+100%29%2A%28c+%2B+3%29+=+6000\"
\n" ); document.write( "This says:
\n" ); document.write( "(revolutions of rear wheel) x(circumference of rear wheel) = distance traveled
\n" ); document.write( "\"6000+-+100c+%2B+18000%2Fc+-+300+=+6000\"
\n" ); document.write( "\"6000c+-+100c%5E2+%2B+18000+-+300c+=+6000c\"
\n" ); document.write( "\"100c%5E2+%2B+300c+-+18000+=+0\"
\n" ); document.write( "\"c%5E2+%2B+3c+-+180+=+0\"
\n" ); document.write( "Completing the square:
\n" ); document.write( "\"c%5E2+%2B+3c+%2B+%283%2F2%29%5E2+=+180+%2B+%283%2F2%29%5E2\"
\n" ); document.write( "\"c%5E2+%2B+3c+%2B+9%2F4+=+720%2F4+%2B+9%2F4\"
\n" ); document.write( "\"%28c+%2B+3%2F2%29%5E2+=+729%2F4\"
\n" ); document.write( "\"c+%2B+3%2F2+=+27%2F2\"
\n" ); document.write( "\"c+=+24%2F2\"
\n" ); document.write( "\"c+=+12\"
\n" ); document.write( "\"c+%2B+3+=+15\"
\n" ); document.write( "The front wheel is 12 ft in circumference
\n" ); document.write( "The rear wheel is 15 ft in circumference
\n" ); document.write( "check:
\n" ); document.write( "\"%286000%2Fc+-+100%29%2A%28c+%2B+3%29+=+6000\"
\n" ); document.write( "\"%286000%2F12+-+100%29%2A%2812+%2B+3%29+=+6000\"
\n" ); document.write( "\"%28500+-+100%29%2A15+=+6000\"
\n" ); document.write( "\"400%2A15+=+6000\"
\n" ); document.write( "\"6000+=+6000\"
\n" ); document.write( "
\n" ); document.write( "
\n" );