document.write( "Question 348666: The chemistry lab keeps two acid solutions. One is 20% acid solutin and the other 35% acid solution. How much 20% and 35% acid solution should be used to prepare 25 liters of a 26% acid solution? \n" ); document.write( "
Algebra.Com's Answer #249320 by Fombitz(32388)\"\" \"About 
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Let \"A\" be the amount of 20% acid solution.
\n" ); document.write( "Let \"B\" be the amount of 35% acid solution.
\n" ); document.write( "Volume:
\n" ); document.write( "1.\"A%2BB=25\"
\n" ); document.write( "Concentration:
\n" ); document.write( "\"20A%2B35B=26%2825%29\"
\n" ); document.write( "2.\"4A%2B7B=130\"
\n" ); document.write( "Multiply eq. 1 by 4 and subtract from eq. 2,
\n" ); document.write( "\"4A%2B7B-4A-4B=130-100\"
\n" ); document.write( "\"3B=30\"
\n" ); document.write( "\"highlight%28+B=10%29\"liters
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A%2B10=25\"
\n" ); document.write( "\"highlight%28+A=15%29\"liters
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