document.write( "Question 348737: The paint is 21 years newer that the brush. The paint is also one fourth as old as the brush. How old is each one? \n" ); document.write( "
Algebra.Com's Answer #249310 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=brush's age \n" ); document.write( "then x-21=paint's age \n" ); document.write( "So our equation to solve is: \n" ); document.write( "x-21=(1/4)x multiply each term by 4 \n" ); document.write( "4x-84=x subtract 4x from each side \n" ); document.write( "4x-4x-84=-4x+x collect like terms \n" ); document.write( "-3x=-84 \n" ); document.write( "x=28 years old---age of the brush \n" ); document.write( "x-21=28-21=7 years old---age of the paint \n" ); document.write( "CK \n" ); document.write( "28-7=21 \n" ); document.write( "21=21---ok \n" ); document.write( "(1/4)*28=7 \n" ); document.write( "7=7---ok\r \n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor \n" ); document.write( " |