document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348704>Question 348704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^4-81xy^3 i need help on how to work it out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249269 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "If I am understanding your question properly, the idea is to simplify by factoring out what each term has in common.  In this case both terms have 3*x in common:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2Ax%5E4-81%2Ax%2Ay%5E3 ALIGN=MIDDLE  ALT=\"3%2Ax%5E4-81%2Ax%2Ay%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%28x%5E3-27%2Ay%5E3%29 ALIGN=MIDDLE  ALT=\"3x%28x%5E3-27%2Ay%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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