document.write( "Question 348530: solve each equation by using the substitution method and the elimination method
\n" ); document.write( "2x+3y=0
\n" ); document.write( "4x+12=9y
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Algebra.Com's Answer #249224 by Fombitz(32388)\"\" \"About 
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Substitution:
\n" ); document.write( "1.\"2x%2B3y=0\"
\n" ); document.write( "2.\"4x-9y=-12\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"2x=-3y\"
\n" ); document.write( "\"-9y=6x\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"4x-9y=-12\"
\n" ); document.write( "\"10x=-12\"
\n" ); document.write( "\"highlight%28x=-6%2F5%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"-9y=6%28-6%2F5%29\"
\n" ); document.write( "\"-9y=-36%2F5\"
\n" ); document.write( "\"highlight%28y=4%2F5%29\"
\n" ); document.write( ".
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\n" ); document.write( "Elimination:
\n" ); document.write( "1.\"2x%2B3y=0\"
\n" ); document.write( "2.\"4x-9y=-12\"
\n" ); document.write( "Multiply eq. 1 by 3 and add the equations together,
\n" ); document.write( "\"6x%2B9y%2B4x-9y=-12\"
\n" ); document.write( "\"10x=-12\"
\n" ); document.write( "\"highlight%28x=-6%2F5%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"-9y=6%28-6%2F5%29\"
\n" ); document.write( "\"-9y=-36%2F5\"
\n" ); document.write( "\"highlight%28y=4%2F5%29\"
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