document.write( "Question 348538: a 40% solution is to be mixed with a 60% solution to obtain 8 liters of a 55% solution. how many liters of each solution should be used \n" ); document.write( "
Algebra.Com's Answer #249207 by Fombitz(32388)\"\" \"About 
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Let \"A\" be the amount of 40% solution.
\n" ); document.write( "Let \"B\" be the amount of 60% solution.
\n" ); document.write( "Volume eqaution:
\n" ); document.write( "1.\"A%2BB=8\"
\n" ); document.write( "Concentration equation:
\n" ); document.write( "\"40A%2B60B=55%288%29\"
\n" ); document.write( "2.\"2A%2B3B=22\"
\n" ); document.write( "Multiply eq. 1 by 2 and subtract it from eq. 2,
\n" ); document.write( "\"2A%2B3B-2A-2B=22-16\"
\n" ); document.write( "\"highlight%28B=6%29\"liters
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B6=8\"
\n" ); document.write( "\"highlight%28A=2%29\"liters
\n" ); document.write( "
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