document.write( "Question 348574: WORD PROBLEM (AGE PROBLEM)\r
\n" ); document.write( "\n" ); document.write( "1. Six years ago Jun was 4 times as old as Joan.In four years, he would be twice as old as Joan. How old are they now?\r
\n" ); document.write( "\n" ); document.write( "2. At present, Pedro's age is 25percent of his father's age.Twenty years from now Pedro's age would be 50percent of his fathers age. How old are they?\r
\n" ); document.write( "\n" ); document.write( "pls help me to solve this problem.. thank you\r
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Algebra.Com's Answer #249187 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
6 years ago
\n" ); document.write( "joan x
\n" ); document.write( "jun 4x
\n" ); document.write( "..
\n" ); document.write( "after 4 years
\n" ); document.write( "joan x+10
\n" ); document.write( "Jun 4x+10
\n" ); document.write( "4x+10=2(x+10)
\n" ); document.write( "4x+10=2x+20
\n" ); document.write( "4x-2x=20-10
\n" ); document.write( "2x=10
\n" ); document.write( "x=5 joan 6 years ago. Now age = 11
\n" ); document.write( "Jun 4x, = 20, 6 years ago. Now age =26 years now
\n" ); document.write( ".......
\n" ); document.write( "Let pedro's age be x ( pedro's age is 1/4 of father'e age OR father is 4 times pedros age)
\n" ); document.write( "father's age = 4x
\n" ); document.write( "..
\n" ); document.write( "20 years later
\n" ); document.write( "pedro = x+20
\n" ); document.write( "Father = 4x+20
\n" ); document.write( "2(x+20)=4x+20
\n" ); document.write( "2x+40 =4x+20
\n" ); document.write( "2x=20
\n" ); document.write( "x=10 pedro's age now
\n" ); document.write( "father= 10*4 = 40 years
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