document.write( "Question 348548: Change the numbers to the indicated base.
\n" ); document.write( "133 to base four\r
\n" ); document.write( "\n" ); document.write( "5881 to base nine
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Algebra.Com's Answer #249183 by Jk22(389)\"\" \"About 
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133 to base four :
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\n" ); document.write( "3(10)=3(4)
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\n" ); document.write( "30(10)=3*10(10)=3*22(4)=3*2(4)+3*20(4)=12(4)+120(4)=132(4)
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\n" ); document.write( "100(10)=10(10)+3*30(10)=22(4)+3*132(4)=22(4)+3*2(4)+3*30(4)+3*100(4)
\n" ); document.write( "=22(4)+12(4)+210(4)+300(4)
\n" ); document.write( "=32(4)+2(4)+1110(4)=100(4)+1110(4)=1210(4)
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\n" ); document.write( "hence 133(10)=3(4)+132(4)+1210(4)=201(4)+1210(4)=2011(4)
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\n" ); document.write( "Verif : 1+4+2*64=5+2*64=128+5=133\r
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\n" ); document.write( "\n" ); document.write( "5881 to base nine (default : from base 10)\r
\n" ); document.write( "\n" ); document.write( "81(10)=9*9=100(9)
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\n" ); document.write( "800(10)=8*100(10)=8*10(10)*10(10)=8*11(9)*11(9)=8=8=8*121(9)=1078(9)
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\n" ); document.write( "5000(10)=5*121(9)*10(10)=5*121(9)*11(9)=5=5*1331(9)
\n" ); document.write( "=6765(9)
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\n" ); document.write( "100(9)+1078(9)+6765(9)=1178(9)+6765(9)=8054(9)
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\n" ); document.write( "Verif : 4+5*9+8*9^3=49+8*729=49+5832=5881
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