document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348563>Question 348563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jogger leaves a given point on a fitness trail running at a rate of 4 miles per hour.  Ten minutes later a second jogger leaves the same location running at 5 miles per hour.  How long will it take the second jogger to overtake the first and how far will they both have traveled at that point? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249172 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jogger A 4 mph <BR>\n" );
document.write( "Jogger B 5 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "difference in speed = 1mph.<BR>\n" );
document.write( "Jogger A leaves 10 minutes early = 1/6 hour<BR>\n" );
document.write( "in1/6 hour he goes 1/6 * 4 = 2/3 miles.\r<BR>\n" );
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document.write( "Jogger B catches up at the rate of 1 mph.<BR>\n" );
document.write( "distance ahead = 2/3 miles<BR>\n" );
document.write( "Time = 2/3  / 1<BR>\n" );
document.write( "= 2/3 hours = 40 minutes<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2/3 * 5 = 10/3 miles = 3.33 miles .from start\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );