document.write( "Question 348503: train a goes 100 miles an hour and train b goes 110mph. train a passes a stop at 1210am and train b passes the same stop at 1222am. What time does train b catch train a? \n" ); document.write( "
Algebra.Com's Answer #249154 by mananth(16946)\"\" \"About 
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train A 100mph
\n" ); document.write( "train B = 110 mph
\n" ); document.write( "...
\n" ); document.write( "train A 1210
\n" ); document.write( "train B 1222
\n" ); document.write( "difference = 12 minutes.
\n" ); document.write( "..
\n" ); document.write( "in 12 minutes train A has traveled (12/60) * 100= 20 miles
\n" ); document.write( "...
\n" ); document.write( "Difference between their speeds = 10 mph.
\n" ); document.write( "train B catches up 10 miles every 1 hour
\n" ); document.write( "it has to catch up 20 miles
\n" ); document.write( "Time = distance / speed
\n" ); document.write( "time 20/10
\n" ); document.write( "= 2hours.
\n" ); document.write( "Train B will catch up at 0222 hours
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