document.write( "Question 348503: train a goes 100 miles an hour and train b goes 110mph. train a passes a stop at 1210am and train b passes the same stop at 1222am. What time does train b catch train a? \n" ); document.write( "
Algebra.Com's Answer #249154 by mananth(16946)![]() ![]() You can put this solution on YOUR website! train A 100mph \n" ); document.write( "train B = 110 mph \n" ); document.write( "... \n" ); document.write( "train A 1210 \n" ); document.write( "train B 1222 \n" ); document.write( "difference = 12 minutes. \n" ); document.write( ".. \n" ); document.write( "in 12 minutes train A has traveled (12/60) * 100= 20 miles \n" ); document.write( "... \n" ); document.write( "Difference between their speeds = 10 mph. \n" ); document.write( "train B catches up 10 miles every 1 hour \n" ); document.write( "it has to catch up 20 miles \n" ); document.write( "Time = distance / speed \n" ); document.write( "time 20/10 \n" ); document.write( "= 2hours. \n" ); document.write( "Train B will catch up at 0222 hours \n" ); document.write( " |