document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348475>Question 348475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 50 Americans, 45 Europeans and 1 Asian are forming a committee and 3 representatives are to be chosen at random to head the committee. Using number of combinations, find probability that the group of three consists of one American, one European and 1 Asian. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249120 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=((50C1)(45C1)(1C1))/96C3<BR>\n" );
document.write( "=(50*45*1)/142880<BR>\n" );
document.write( "=2250/142880<BR>\n" );
document.write( "=.0157  probability that the group of three consists of one American, one European and 1 Asian.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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