document.write( "Question 39429: Please Help!
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document.write( "The length of a rectangle is 3 more than the width. If the length is doubled and 4 is added to the width, a new rectanlge is formed with an area of 104 square units larger than the area of the original rectangle. find the dimensions of the original rectangle. \n" );
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Algebra.Com's Answer #24910 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Length of a rectangle = x+3 \n" ); document.write( "Width = x \n" ); document.write( "Area = \n" ); document.write( "Length doubled = 2(x+3) -->2x+6 \n" ); document.write( "4 added to the width = x+4 \n" ); document.write( "Forms 104 larger area = \n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplfy and remove the negative \n" ); document.write( "x=5 \n" ); document.write( "5+3=8 \n" ); document.write( "Hence, the width is 5cm and the length is 8cm. \n" ); document.write( "Paul. \n" ); document.write( " |