document.write( "Question 39429: Please Help!
\n" ); document.write( "The length of a rectangle is 3 more than the width. If the length is doubled and 4 is added to the width, a new rectanlge is formed with an area of 104 square units larger than the area of the original rectangle. find the dimensions of the original rectangle.
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Algebra.Com's Answer #24910 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
Length of a rectangle = x+3
\n" ); document.write( "Width = x
\n" ); document.write( "Area = \"%28x%2B3%29%28x%29=x%5E2%2B3x\"
\n" ); document.write( "Length doubled = 2(x+3) -->2x+6
\n" ); document.write( "4 added to the width = x+4
\n" ); document.write( "Forms 104 larger area = \"x%5E2%2B3x%2B104\"
\n" ); document.write( "Equation:
\n" ); document.write( "\"%282x%2B6%29%28x%2B4%29=x%5E2%2B3x%2B104\"
\n" ); document.write( "\"2x%5E2%2B14x%2B24=x%5E2%2B3x%2B104\"
\n" ); document.write( "\"x%5E2%2B11x-80=0\"
\n" ); document.write( "\"x+=+%28-11+%2B-+sqrt%28+11%5E2-4%2A1%2A-80+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "Simplfy and remove the negative
\n" ); document.write( "x=5
\n" ); document.write( "5+3=8
\n" ); document.write( "Hence, the width is 5cm and the length is 8cm.
\n" ); document.write( "Paul.
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