document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348374>Question 348374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sum of 3 numbers is 137. The second number is 4 more than 2 times the first number. The third number is 5 less than 3 times the first number. Find the 3 numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #249070 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=249070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X BE THE FIRST NUMBER.<BR>\n" );
document.write( "2X+4 IS THE SECOND NUMBER.<BR>\n" );
document.write( "3X-5 IS THE THIRD NUMBER.<BR>\n" );
document.write( "X+(2X+4)+(3X-5)=137<BR>\n" );
document.write( "6X-1=137<BR>\n" );
document.write( "6X=137+1<BR>\n" );
document.write( "6X=138<BR>\n" );
document.write( "X=138/6<BR>\n" );
document.write( "X=23 ANS. FOR THE FIRST NUMBER.<BR>\n" );
document.write( "2*23+4=46+4=50 ANS. FOR THE SECOND NUMBER.<BR>\n" );
document.write( "3*23-5=69-5=64 ANS. FOR THE THIRD NUMBER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "23+50=64=137<BR>\n" );
document.write( "137=137<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );